Question

Question #3285c

Answer 1

`x=25g`

Explanation:

The initial mass of the solution was 100g
As 50% (w/w) solute was present in 100g solution , we can say the mass of the solute in initial solution was 50g

After addition of x g solute in 100g solution the changed mass of solution became (x+100)g and total amount of solute became (x+50)g.
So the percentage of solute in final solution became 60%.

So

`(x+50)/(x+100)xx100=60`

`=>(x+50)/(x+100)=60/100=0.6`

`=>x+50=0.6(x+100)`

`=>x+50=0.6x+60`

`=>x-0.6x=60-50`

`=>0.4x=10`

`=>x=10/0.4=25`