Question

How many vertical asymptotes does the graph of `f(x)=3/(5(x+9))`?

Answer 1

one at x = -9

Explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non-zero for this value then it is a vertical asymptote.

solve: `5(x+9)=0rArrx=-9" is the asymptote"`
graph{(3)/(5(x+9)) [-10, 10, -5, 5]}