How do you find the limit of # (3 x^4 + 4) / ((x^2 - 7)(4 x^2 - 1)) # as x approaches infinity? Calculus Limits Infinite Limits and Vertical Asymptotes 1 Answer Cesareo R. Sep 28, 2016 #3/4# Explanation: # (3 x^4 + 4) / ((x^2 - 7)(4 x^2 - 1))=x^4/x^4(3+4/x^4)/((1-7/x^2)(4-1/x^2))# so #lim_(x->oo) (3 x^4 + 4) / ((x^2 - 7)(4 x^2 - 1)) = lim_(x->oo)(3+4/x^4)/((1-7/x^2)(4-1/x^2)) = 3/4# Answer link Related questions How do you show that a function has a vertical asymptote? What kind of functions have vertical asymptotes? How do you find a vertical asymptote for y = sec(x)? How do you find a vertical asymptote for y = cot(x)? How do you find a vertical asymptote for y = csc(x)? How do you find a vertical asymptote for f(x) = tan(x)? How do you find a vertical asymptote for a rational function? How do you find a vertical asymptote for f(x) = ln(x)? What is a Vertical Asymptote? How do you find the vertical asymptote of a logarithmic function? See all questions in Infinite Limits and Vertical Asymptotes Impact of this question 1261 views around the world You can reuse this answer Creative Commons License