Question #4e641

1 Answer
Sep 29, 2016

This is an odd function.

Explanation:

To check if a function f(x) is odd or even (or neither) you have to calculate f(-x) and compare the calculated value with f(x).

  • If f(-x)=f(x) then f(x) is even,

  • if f(-x)=-f(x) then f(x) is odd.

Here we have:

f(x)=x^3+7x

f(-x)=(-x)^3+7*(-x)

f(-x)=-x^3-7x

We see that the value is an opposite expression to f(x).

f(-x)=-f(x), so the function is odd

Other way to see if the function is even or odd is to look at the function's graph.

  • if the graph is symetrical according to Y axis then the function is even.Example: y=x^2+2

graph{x^2+2 [-10, 10, -5, 5]}

  • If the graph is symetrical according to the origin (0,0) then it is odd. Example: x^3+7x

graph{x^3+7x [-3, 3, -50, 50]}