How do you use the limit definition to find the slope of the tangent line to the graph #f(x) = 2x+4# at (1, 6)? Calculus Derivatives Tangent Line to a Curve 1 Answer Tazwar Sikder Sep 29, 2016 #2# Explanation: We have: #f(x) = 2 x + 4# #=> f'(x) = lim_(h -> 0) (f(x + h) - f(x)) / (h)# #=> f'(x) = lim_(h -> 0) (2 (x + h) + 4 - 2 x + 4) / (h)# #=> f'(x) = lim_(h -> 0) (2x + 2 h - 2 x) / (h)# #=> f'(x) = lim_(h -> 0) (2h) / (h)# #=> f'(x) = 2# Answer link Related questions How do you find the equation of a tangent line to a curve? How do you find the slope of the tangent line to a curve at a point? How do you find the tangent line to the curve #y=x^3-9x# at the point where #x=1#? How do you know if a line is tangent to a curve? How do you show a line is a tangent to a curve? How do you find the Tangent line to a curve by implicit differentiation? What is the slope of a line tangent to the curve #3y^2-2x^2=1#? How does tangent slope relate to the slope of a line? What is the slope of a horizontal tangent line? How do you find the slope of a tangent line using secant lines? See all questions in Tangent Line to a Curve Impact of this question 1138 views around the world You can reuse this answer Creative Commons License