Question

How do you multiply `(6g + 4) ( g - 20)`?

Answer 1

`= 6g^2 -116g -80`

Explanation:

1. Expand the brackets by multiplying each term in the first bracket with each term in the second bracket. (eg. `(a+b)(c+d) = ac + ad + bc + bd`) The signs for each term should be maintained.
   Therefore,
   `(6g + 4)(g - 20)`
   `= (6g)(g) + (6g)(-20) + (4)(g) + (4)(-20)`
   `= 6g^2 -120g + 4g -80`
2. Group like terms
   `= 6g^2 -116g -80`

Answer 2

`6g^2-116g-80`

Explanation:

`(6g+4)(g-20)`

Multiply each term in the first binomial by each term in the second.
Some teachers refer to this as FOIL: multiply the First 2 terms, then the Outer 2 terms, then the Inner 2 terms, then the Last 2 terms.

`(6g*g) +(6g*-20) +(4*g)+(4*-20)`

`6g^2-120g+4g-80`

`6g^2-116g-80`