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Answer 1 · 2016-10-01T03:03:26

You are to determine the number of molecules of $NH_3$ .

One molecule of $NH_3$ contains 3 atoms of Hydrogen.So to produce one mole of $NH_3$ we require $3/2molH_2$ The following equation also supports that

$N_2+3H_2->2NH_3$

So 1 mole $H_2$ produces $2/3mol NH_3$
Hydrogen taken $=7.98xx10^-4g$

$=1.64xx10^-4gxx1/(2.016g/"mol")$

where molar mass of Hydrogen $=2.016g/"mol"$

So no.of moles of $NH_3$ produced
$=2/3xx1.64xx10^-4gxx1/(2.016g/"mol")$

So no.of molecules of $NH_3$ produced

$=2/3xx1.64xx10^-4gxx1/(2.016g/"mol")xx6.023xx10^23"molecule"/"mol"$
$~~3.27xx10^19$ molecules