Question #94595

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Answer 1 · 2016-10-03T01:45:55

#-67#

Let the 3 consecutive integers be #-(x-1), -x, -(x+1)#
#=> -204=-(x-1+x+x+1)#
#=> -204=-3x#
#=>68=x#

#=> -(x-1)=-(68-1)=-67#
#-x=-68#
#-(x+1)=-(68+1)=-69#

#=># the largest of the3 consecutive integers #=-67#

Answer 2 · 2016-10-03T01:46:34

The three consecutive integers are #-69. -68, -67#
The largest is #-67#

Let #x=# the first integer.

The second consecutive integer is #x+1#

The third consecutive integer is #x+2#

If the sum of the three integers is #-204#...

#x + x+1+x+2=-204#

#3x+3=-204#

#color(white)(aa)-3color(white)(aaaa)-3#

#color(white)(aa)3xcolor(white)(a^1)=-207#

#color(white)(a)(3x)/3color(white)(a^1)=-207/3#

#color(white)(a^1)xcolor(white)(aa^1)=-69#

#x+1=-68#

#x+2=-67#

The three consecutive integers are #-69. -68, -67#

The largest is #-67#