How many #"hydrogen ATOMS"# are present in a #23.7*g# mass of #"methane"#?

1 Answer
anor277
Oct 3, 2016

There are approx. #N_Axx4xx2# hydrogen atoms in such a mass of methane.

Explanation:

In #16.04*g# methane, there are #N_A# methane molecules, where #N_A="Avogadro's number"=6.022xx10^23#.

And so #"moles of methane"# #=# #(23.7*g)/(12.04*g*mol^-1)# #=# #1.97*mol#

And thus #"atoms of hydrogen"# #=# #(23.7*g)/(12.04*g*mol^-1)xx"4 H atoms"*mol^-1xxN_A" H atoms"#

#~=# #4.80xx10^24" hydrogen atoms"#

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