Question

The perimeter of a rectangle is 56 inches. The length is 4 more than 3 times the width. What are the dimensions of the rectangle?

Answer 1

`22 and 6` `"are the dimensions"`

Explanation:

`color(blue)("Perimeter of rectangle"=2(l+w)`

Where

`color(orange)("l is length and w is width"`

We know that, the width is `4` more than `3` times the width

`:."Length"=3w+4`

Solve

`rarr2(l+w)=56`

`rarr2(3w+4+w)=56`

`rarr2(4w+4)=56`

`rarr4w+4=56/2`

`rarr4w+4=28`

`rarr4w=28-4`

`rarr4w=24`

`rarrw=24/4`

`color(blue)(rArrw=6`

We know that the width is `6`.So, the length will be `3(6)+4=22`