How do you solve #3( - 3x + 5) - 3x - 4= - 1#?

1 Answer
Jim G.
Oct 6, 2016

#x=1#

Explanation:

First step is to distribute the bracket on left side of the equation.

#-9x+15-3x-4=-1#

collect like terms on left side.

#rArr-12x+11=-1#

subtract 11 from both sides.

#-12xcancel(+11)cancel(-11)=-1-11#

#rArr-12x=-12#

To solve for x, divide both sides by - 12.

#(cancel(-12) x)/cancel(-12)=(-12)/(-12)#

#rArrx=1" is the solution"#

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