How do you solve #|7- 3x | \leq 4#?

1 Answer
Binayaka C.
Oct 6, 2016

Solution: #x>=1 and x <= 11/3#; In interval notation; #[1,11/3]#

Explanation:

1) #|7-3x| <= 4 or 7-3x <= 4 or -3x<= -3 or 3x>=3 or x>=1# OR
2) #|7-3x| <= 4 or 7-3x >= -4 or -3x >= -11 or 3x <= 11 or x <=11/3#
Solution: #x>=1 and x <= 11/3#; In interval notation; #[1,11/3]#[Ans]

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