How do you solve $5 (3 y - 2) = 20$ $5( 3y - 2) = 20$ ?

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Answer 1 · 2016-10-06T21:11:13

$y = 2$ $y = 2$

First we expand the brackets

$5 (3 y - 2) = 20 \to$ $5 (3y-2) = 20 to$

$15 y - 10 = 20$ $15y - 10 = 20$

Then add $10$ $10$ to both sides

$15 y = 30$ $15y = 30$

Finally we divide by $15$ $15$

$y = 2$ $y = 2$

How do you solve 5(3y−2)=205( 3y - 2) = 20?