What is the percentage by mass of #SO_3#?

1 Answer
anor277
Oct 7, 2016

#"% sulfur by mass"# #=# #(32.06*g*mol^-1)/(80.066*g*mol^-1)xx100%# #=# #??#

Explanation:

#"% sulfur by mass"# #=# #(32.06*g*mol^-1)/(80.066*g*mol^-1)xx100%# #=# #??#

#"% oxygen by mass"# #=# #(3xx16.00*g*mol^-1)/(80.066*g*mol^-1)xx100%# #=# #??#

The sum of the individual percentages #=100%#; why?

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