Question

How do you integrate `int (x^3+x)/x dx`?

Answer 1

`x^3/3+x+C`

Explanation:

First start off by simplifying:

`int(x^3+x)/xdx` =
`intx^3/x+x/xdx` =
`intx^2+1dx` =
`intx^2dx+int1dx` =
`x^3/3+x+C`