How do you evaluate the limit #(s-1)/(s^2-1)# as s approaches #1#?

1 Answer
Oct 8, 2016

#lim_(s->1) (s-1)/(s^2-1) = 1/2#

Explanation:

Note that #s^2-1 = (s-1)(s+1)#, so we can factor and simplify the given rational expression:

#(s-1)/(s^2-1) = (color(red)(cancel(color(black)(s-1))))/((color(red)(cancel(color(black)(s-1))))(s+1)) = 1/(s+1)#

with exclusion #s != 1#

The simplified rational expression describes a function identical to the original one, except that the original is undefined at the point #s=1#.

Hence:

#lim_(s->1) (s-1)/(s^2-1) = lim_(s->1) 1/(s+1) = 1/2#