Question #44937

1 Answer
Henry W.
Oct 8, 2016

#69.69% K#, #28.52%O#, #1.79% H#

Explanation:

Find the molecular mass of the whole compound:
#AM(K)=39.1 AMU#
#AM(O)=16.00 AMU#
#AM(H)=1.008 AMU#
#39.1+16+1.008=56.108#

Find the percentage of each element within the compound:
#%(K)=100#x#39.1/56.108=69.69%#
#%(O)=100#x#16/56.108=28.52%#
#%(H)=100#x#1.008/56.108=1.79%#

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