How do you solve #4+ ( 4+ 2) \times 5#?

1 Answer
Clara M.
Oct 8, 2016

#34#

Explanation:

First you take care of what is in parentheses/brackets, then exponential or square root, division, multiplication, addition and subtraction is the last one.
That is the rule in Math.

So, #4+(4+2)xx5=4+6xx5=4+30=34#
You can even put the #6xx5# in parentheses for you to see that you have #xx# versus #+#, which will look like #4+(6xx5)=4+30=34#

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