How do you solve 3( y - 8)^{2} = 96?

1 Answer
Oct 9, 2016

y=8+4√2, 8-4√2

Explanation:

  1. Divide both sides of the equation by 3: (y-8)^2=32
  2. Take the square root of both sides of the equation : y-8=4√2, y-8=-4√2
  3. Add 8 to both sides of both equations: y=8+4√2, y=8-4√2