What is the solubility of #PbI_2#?

1 Answer
anor277
Oct 10, 2016

You need a #K_"sp"# value for #PbI_2#.

Explanation:

Plumbous iodide is insoluble in aqueous solution, and thus the reaction would lead to a yellow precipitate of #PbI_2# as shown.

#Pb(NO_3)_2(aq) + 2KI(aq) rarr PbI_2(s)darr + 2KNO_3(aq)#.

Now of course we could calculate the concentration of #PbI_2# that does go up into solution, but for this need a #K_"sp"# value for #PbI_2#.

#PbI_2(s) rightleftharpoons Pb^(2+) + 2I^-#

#K_"sp"=[Pb^(2+)][I^-]^2# #=# #??#

Related questions
See all questions in Molarity
Impact of this question
1580 views around the world
You can reuse this answer
Creative Commons License