Question #2ef3f

Oct 10, 2016

#f'(x)=3sin^2xcosx-3cosx = -3cos^3x#

Use the chain rule to differentiate #sin^3 x = (sinx)^3#

#f'(x)=3sin^2xcosx-3cosx# which can be rewritten

# = 3cosx(sin^2x-1)#

# = -3cosx(1-sin^2x)#

# = -3cosx(cos^2x)#

# = -3cos^3x#

1239 views around the world

You can reuse this answer
Creative Commons License