How do you solve #12 (x-20)=-48#?

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Answer 1 · 2016-10-12T01:22:26

#x=16#

Solve: #12(x-20)=-48#

Expand the left side of the equation using the distributive property: #a(b+c)=ab+ac#.

#12x-240=-48#

Add #240# to both sides.

#12x=-48+240#

Simplify.

#12x=192#

Divide both sides by #12#.

#x=192/12#

Simplify.

#x=16#