How do you find the definite integral for: (6x+3)dx for the intervals [3, 9]? Calculus Introduction to Integration Formal Definition of the Definite Integral 1 Answer Henry W. Oct 12, 2016 234 Explanation: int_3^9(6x+3)dx=[3x^2+3x]_3^9 =[3(9)^2+3(9)]-[3(3)^2+3(3)] =270-36=234 Answer link Related questions What is the Formal Definition of the Definite Integral of the function y=f(x) over the... How do you use the definition of the definite integral? What is the integral of dy/dx? What is an improper integral? How do you calculate the double integral of (xcos(x+y))dr where r is the region: 0 less than... How do you apply the evaluation theorem to evaluate the integral 3t dt over the interval [0,3]? What is the difference between an antiderivative and an integral? How do you integrate 3x^2-5x+9 from 0 to 7? Question #f27d5 How do you evaluate the definite integral int sqrtt ln(t)dt from 2 to 1? See all questions in Formal Definition of the Definite Integral Impact of this question 3062 views around the world You can reuse this answer Creative Commons License