How do you solve #\sqrt { y + 5 } = 4 - \sqrt { y - 1 6 }#?

1 Answer
Cesareo R.
Oct 12, 2016

No feasible solution.

Explanation:

The feasibility conditions are

#y+5 ge 0# and #y - 16 ge 0# so

#y ge 16# is the mandatory condition.

Now, substituting #y=16# in the equation, follows

#sqrt(y+5)=4# but if #y ge 16# this condition is not attainable. So no feasible solution.

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