Question

The volume of a fixed amount of gas is doubled, and the absolute temperature is doubled. According to the ideal gas law, how has the pressure of the gas changed?

Answer 1

Given that `P=(nRT)/V`, for an ideal gas, the pressure would be unchanged.

Explanation:

`P_1=(nRT)/V`

`P_2=(nRxx2T)/(2V)` `=` `(nRxxcancel2T)/(cancel2V)` `=` `P_1`.

Capisce?