How do you solve #6^x=216#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer KillerBunny Oct 13, 2016 #x=3# Explanation: You can decompose #216# to see its prime factors: #216 \div 2 = 108# #108 \div 2 = 54# #54 \div 2 = 27# #27 \div 3 = 9# #9 \div 3 = 3# #3 \div 3 = 1# Thus, #2016 = 2^3 * 3^3# But this means that #2016 = (2*3)^3=6^3#, and thus #x=3# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 3736 views around the world You can reuse this answer Creative Commons License