How do you order these numbers from least to greatest: #-2, 0.75, 1/4, -3/2#?

2 Answers
Oct 14, 2016

The order from the least to the greatest number is #-2,-3/2,1/4,0.75#

Explanation:

#0.75=75/100=3/4# if you divide both #75# and #100# by #25#, you find #3/4#

#1/4=0.25#

#-3/2=-1.5#

and you also have #-2#

Positive numbers are greater than negative numbers.

For positive numbers, you know that #2# is greater than #1#, so the same thing apply for #0.75# and #0.25# (if the point zero in front bothers you, try to look at them as #75# and #25#)

#=>0.75# is greater than #0.25#

For negative numbers, it is the opposite #-2# is smaller than #-1#, which means #-2# is smaller than #-1.5# or #-1.5# is bigger than #-2#

Now, put back #-1.5# and #0.25# in the fractional form they gave you, which means #-3/2# and #1/4# respectively.

So, the order from the least to the greatest number is #-2,-3/2,1/4,0.75#

Let me know if you have any question

I hope this helps :)

Oct 14, 2016

#-2 < -3/2 < 1/4 < 0.75#

Explanation:

Before you can compare any numbers, they need to be in the same format. Decimals is the easiest form to use for comparing.

#-2 = -2.000#

#0.75 = 0.75#

#1/4 = 0.25#

#-3/2 = -1.50#

Now we can arrange them:

#-2 < -1.5 < 0.25 < 0.75#

Using the original numbers gives us:

#-2 < -3/2 < 1/4 < 0.75#