How many moles of #N# are in 0.217 g of #N_2O#?

1 Answer
anor277
Oct 14, 2016

There are twice the molar quantity of nitrogen atoms in nitrous oxide, i.e. #1xx10^-2*mol#.

Explanation:

#"Moles of nitrous oxide"# #=# #(0.217*g)/(44.013*g*mol^-1)# #=# #5xx10^-3*mol#.

Given the composition of #N_2O#, there are this #2xx5xx10^-3*mol# of nitrogen atoms.

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