Question

What is the acceleration during takeoff of a jumbo jet with a mass of 30,000 kg when the thrust for each of its four engines is 30,000 N?

Answer 1

Force = mass times acceleration, or `F=mxxa`

Explanation:

This can be reworked to `a=F/m`

`a=(4xxcancel30000N)/(cancel30000kg)=(4N)/(kg)`

But since the Newton is defined as `N=kg*m//s^2`
We get:
`(4N)/(kg)=(4cancel(kg)*m//s^2)/(cancel(kg))=4m//s^2`