Question

Question #959a1

Answer 1

`-40, -38, -36`

Explanation:

Let `2n` represent the least of the even integers. Then, as the integers are consecutive even integers, we have the next two as `2(n+1)` and `2(n+2)`. Their sum is `-114`, giving us the equation

`2n+2(n+1)+2(n+2) = -114`

`=> 2n+(2n+2)+(2n+4) = -114`

`=> 6n+6 = -114`

`=> 6n = -114-6 = -120`

`=> n = -120/6 = -20`

`=>2n = -40, 2(n+1) = -38, 2(n+2) = -36`

If we check, we find that their sum is `-114` as desired.

Thus, our three consecutive even integers are `-40, -38, -36`.