Question

How do you solve `3sec^2(x)=4`?

Answer 1

`x=pi/6,-pi/6,(5pi)/6,-(5pi)/6`

Explanation:

`secx=1/cosx`
so `3/cos^2x=4`
Reaarranging
`cos^2x=3/4`
`cosx=+-(sqrt3)/2`
`x=pi/6,-pi/6,(5pi)/6,-(5pi)/6`