How do you solve #ln e^(sqrt{2})#?
1 Answer
Oct 18, 2016
The value of this expression is
Explanation:
This question ca be answered using the definition of logarythm (here natural
According to a definition:
#log_a b=c iff a^c=b#
So we are looking for a number to which the base has to be risen to get the value of
In the given example we are looking for a number to which we have to raise