How do you solve #(x + 7) ^ { 1/ 2} + 7= 2#?

1 Answer
Oct 18, 2016

#color(green)(x=18,-32#

Explanation:

#color(blue)((x+7)^(1/2)+7=2#

#rarr(x+7)^(1/2)=2-7#

#rarr(x+7)^(1/2)=-5#

We know that #color(brown)(y^(1/2)=sqrty#

#rarr+-sqrt(x+7)=-5#

The symbol #+-# means #"plus or minus"#

Take the square of both sides to remove the radical sign

#rarr+-(sqrt(x+7))^2=-5^2#

#rarr+-(x+7)=25#

Therefore,

#color(orange)(+(x+7)=25#

#color(lightblue)(-(x+7)=25#

Solve both the equations

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

#rarrcolor(orange)(x+7=25#

#rarrcolor(orange)(x=25-7#

#rArrcolor(green)(x=18#

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

#rarrcolor(lightblue)(-x-7=25#

#rarrcolor(lightblue)(-x=25+7#

#rarrcolor(lightblue)(-x=32#

#rArrcolor(green)(x=-32#

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Hope this helps...!!! :)