If $A= <4, 9 ,-1 >$ and $B= <9 ,-1 ,8 >$ , what is $A*B -||A|| ||B||$ ?

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If $A= <4, 9 ,-1 >$ and $B= <9 ,-1 ,8 >$ , what is $A*B -||A|| ||B||$ ?

1 Answer

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Answer 1 · 2016-10-20T18:41:37

The answer is $19-sqrt98*sqrt146=$

Explanation:

The dot product is $vecA.vecB=36-9-8=19$
Norm of $∥vecA∥=sqrt(16+81+1)=sqrt(98)$
Norm of $∥vecB∥=sqrt(81+1+64)=sqrt(146)$
So the result is $=vecA.vecB-∥vecA∥*∥vecB∥=19-sqrt98*sqrt146$

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If $A= <4, 9 ,-1 >$ and $B= <9 ,-1 ,8 >$ , what is $A*B -||A|| ||B||$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

If A= <4, 9 ,-1 >A= <4, 9 ,-1 > and B= <9 ,-1 ,8 >B= <9 ,-1 ,8 >, what is A*B -||A|| ||B||A*B -||A|| ||B||?

1 Answer

Explanation:

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If $A= <4, 9 ,-1 >$ and $B= <9 ,-1 ,8 >$ , what is $A*B -||A|| ||B||$ ?