How do you solve #\frac{2x-1}{5}=\frac{3x+1}{8}#?

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Answer 1 · 2016-10-20T21:32:28

#x=13#

Because this is a proportion, you cross multiply

#8(2x-1)#

and

#5(3x+1)#

Then, set them equal to each other

#8(2x-1)=5(3x+1)#

Distribute the #8# through the left set of parenthesis and the #5# through the second set of parenthesis

#16x-8=15x+5#

Add #8# on both sides of the equation

#16x=15x+13#

Subtract #15x# on both sides of the equation

#x=13#