How do you find two consecutive odd integers such that 2 times the lesser is 19 less than 3 times the greater?

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Answer 1 · 2016-10-21T09:14:28

The numbers are #13 and 15#

Consecutive odd numbers differ by 2.
If the smaller one is called #x#, the larger one will be #x+2#

We will be working with 2 terms which differ by 19.

This can be written in 3 different ways. Use the form which makes the most sense to you. They are all correct.

#"smaller" +19 = "BIGGER"" "larr# I will use this one

#"BIGGER - smaller" = 19#

#"BIGGER" - 19 = "smaller"#

#2x +19 = 3(x+2)#

#2x+19 = 3x +6" "larr# move x terms to one side

#19-6 = 3x-2x#

#13 = x#

#x=13" "larr# the first odd number.

The next odd number is #15#.