How do you write the first six terms of the sequence #a_n=n/(n+1)#?

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Answer 1 · 2016-10-21T16:03:07

The #n# subscript tells us which term of the sequence it is.

so #u_1# is the first term so #n=1# and we substitute #n=1# into the expression. #u_2,# is when # n=2 # etc.

we have therefore:

#a_n=n/(n+1)#

#a_1=1/(1+1)=1/2#

#a_2=2/(2+1)=2/3#

#a_3=3/(3+1)=3/4#

#a_4=4/(4+1)=4/5#

#a_5=5/(5+1)=5/6#

#a_6=6/(6+1)=6/7#