How do you solve #-3< 4x + 5#?

1 Answer
EZ as pi
Oct 22, 2016

#-2 < x#

Explanation:

Treat an inequality in exactly the same way as an equation, unless you multiply or divide by a negative, in which case the inequality sign changes around,

First you need to isolate the #x-# term.

#-3 <4x+5" "# subtract 5 from each side.

#-3 -5 < 4x +5 -5#

#-8/4 < 4/4x" "# now isolate #x: div4 #

#-2 < x#

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