How do you divide #(5x+5)/(x-2) -: (x^2-1)/(x^2-4x+4)#?

1 Answer
Daniel L.
Oct 23, 2016

The end value is: #(5*(x-2))/(x-1)#. See explanation.

Explanation:

#(5x+5)/(x-2)-:(x^2-1)/(x^2-4x+4)=#

#=(5*(x+1))/(x-2)-:((x-1)(x+1))/((x-2)^2)=#

#=(5*(x+1))/(x-2)xx((x-2)^2)/((x-1)(x+1))=#

#=(5*cancel((x+1)))/cancel(x-2)xx((x-2)cancel((x-2)))/((x-1)(cancel(x+1)))=#

#=(5*(x-2))/(x-1)#

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