Question

How do you simplify `(-7+6i)/(9-4i)` and write the complex number in standard form?

Answer 1

`(-87+26i)/85`

Explanation:

`(-7+6i)/(9-4i)*(9+4i)/(9+4i)->`multiplying by the conjugate of denominator

`=((-7+6i)(9+4i))/(81-4i^2)=(-63-28i+54i-24)/(81+4)`

`=(-87+26i)/85`