What is the arc length of f(t)=(3t-4,t^3-2t) over t in [-1,2]?

1 Answer
Oct 23, 2016

Integration by WolframAlpha
L = 28.7405

Explanation:

dx/dt = 3

dy/dt = 3t^2 - 2

Let L = the arclength

L = int_a^bsqrt((dx/dt)^2 + (dy/dt)^2)dt

Substituting in our values:

L = int_-1^2sqrt((9)^2 + (3t^2 - 2)^2)dt

Integration by WolframAlpha

L = 28.7405