Question

What mass of lithium hydroxide is need to prepare a `250*mL` volume of `"LiOH"` at `0.33*mol*L^-1` concentration?

Answer 1

We require an approximate mass of `2.0*g` of `LiOH`.

Explanation:

`"Concentration"` `=` `"Moles of solute"/"Litres of solution"`. And thus the typical units of concentration are `mol*L^-1`.

We want to make a `250*mL` volume of `0.33*mol*L^-1` concentration. And thus we need `0.250*Lxx0.33*mol*L^-1` `=` `0.0825*mol` of `LiOH` solute.

And this molar quantity has a mass of `0.0825*molxx23.95*g*mol^-1` `=` `1.98*g`