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Answer 1 · 2016-10-25T12:10:06

We are to determine first the molar mass of blue vitrol,cupric sulphate pentahydrate- $CuSO_"4".5H_2O$ using atomic mass of the constituent elements.

Atomic mass of

$Cu->63.5" g/mol"$

$S->32" g/mol"$

$O->16" g/mol"$

$H->1" g/mol"$

Molar mass of $CuSO_"4".5H_2O$

$=63.5+32+4*16+5(2*1+16)=249.5" g/mol"$

400mL or 0.4L 0.25M $CuSO_"4".5H_2O$ solution contains $0.4xx0.25=0.1" mol"$ solute which will have mass
$=0.1" mol"xx249.5 g/"mol"=24.95g$ solute.