Question

Question #5bff8

Answer 1

We are to determine first the molar mass of blue vitrol,cupric sulphate pentahydrate-`CuSO_"4".5H_2O` using atomic mass of the constituent elements.

Atomic mass of

`Cu->63.5" g/mol"`

`S->32" g/mol"`

`O->16" g/mol"`

`H->1" g/mol"`

Molar mass of `CuSO_"4".5H_2O`

`=63.5+32+4*16+5(2*1+16)=249.5" g/mol"`

400mL or 0.4L 0.25M `CuSO_"4".5H_2O` solution contains `0.4xx0.25=0.1" mol"` solute which will have mass
`=0.1" mol"xx249.5 g/"mol"=24.95g` solute.