How do you solve #5x + 14^ { 2} = - 7#?

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Answer 1 · 2016-10-25T14:52:07

#x = -40 3/5 = -40.6#

#5x +14^2 = -7#

Do not be put off by the #14^#! - It is just the number 196.

#5x +196 = -7" "larr# isolate the term in #x#

#5x = -7-196#

#5x = -203" "larr# isolate #x#

#x = -203/5#

#x = -40 3/5 = -40.6#