How do you solve #\sqrt { 5x ^ { 2} - 9} = 2x#?

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Answer 1 · 2016-10-26T05:21:35

#x=3#

#sqrt((5x^2)-9)=2x #

square both sides

#5x^2-9=4x^2#

subtract the #4x^2# across

#x^2-9=0#

add the 9 across

#x^2=9#

Take the square root of both sides

#x=3#