Question

A `4.7x 10` ohm resistor has a current of `1.27 x 10^-1` amp flowing in it. What is the potential difference across the resistor?

Answer 1

5.969 volt

Explanation:

from Ohm's law we know that

`V=IR`

here,

`I=1.27X10^(-1)amp`
`r=4.7X10 Omega`

so,
potential difference `V=1.27X10^(-1)X4.7X10 vol t`
`=5.969 vol t`