How do you solve #-2x - 6> 2#?
1 Answer
Oct 27, 2016
Explanation:
Leave the - 2x on the left side of the inequation and collect numeric values on the right side.
add 6 to both sides.
#-2xcancel(-6)cancel(+6)>2+6#
#rArr-2x>8# divide both sides by - 2.
Remember that when we multiply/divide an inequation by a negative value we must
#color(blue)"reverse the inequality sign"#
#(cancel(-2) x)/cancel(-2)<8/(-2)larr" reverse sign"#
#rArrx<-4" is the solution"#
