How do you solve #8( - 4m + 3) = 20#?

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Answer 1 · 2016-10-28T12:43:05

To solve this problem first multiple by 8 across the expression in parenthesis to get:

#-32m + 24 = 20#

Then subtract 24 from each side to get:

#-32m = -4#

Then divide by -32 on each side to get:

#m = (-4)/-32#

#m = 4/32#

#m = 1/8#