Question

How do you evaluate the definite integral `int 4-x` from `[0,2]`?

Answer 1

The integral `int_0^2(4-x)dx=6`

Explanation:

You have to use `intx^ndx=x^(n+1)/(n+1)+C` `(n!=-1)`
`int(4-x)dx=int4dx-intxdx=4x-x^2/2`

then you have to put the limits

`int_0^2(4-x)dx=(4x-x^2/2)_0^2=(4*2-2*2/2)=6`