How do you solve #\frac { 1} { 2} ( 4x - 2) = 8x + 1#?

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Answer 1 · 2016-10-28T17:45:55

#x=-1/3#

#x=??#

#1/2(4x-2)=8x+1#

#rArr1/2(2(2x-1))=8x+1#

#rArr2x-1=8x+1#

#rArr2x-8x=1+1#

#rArr-6x=2#

#rArrx=-2/6#

#rArrx=-1/3#